
Graphs of Absolute Value Equations - Socratic
Questions How do you graph absolute value equations on a coordinate plane? How do you create a table of values for an absolute value equation? How do you know which x values to choose …
How do you graph # f (x)=x^2+2#? - Socratic
So, #f (x)# is a concave up parabola and has an absolute minimum value of #2# at #x=0#. The graph of #f (x)# is ahown below.
How do you write #y = -2|x-4|+4# as a piecewise function? - Socratic
The piecewise function is y= { (-2x+12 if x>=4), (2x-4 if x<4):} The function is y=-2|x-4|+4 x-4>=0, =>, x>=4 Therefore, y=-2|x-4|+4= { (-2 (x-4)+4 if x>=4), (-2 ...
Site Map - Absolute Value Questions and Videos | Socratic
What is the value of #2^ (-|-2|)#? How do you write an absolute value equation that could be used to express the distance from point P to the origin is 5 more than twice the value of P? How do …
Site Map - Trigonometry Lessons | Socratic
Find the exact value of: csc^2 (17pi/4) How do I do problems with the sin, cos, tan...etc raised to the power of 2? Find the exact value of sin^3 3645° Do I go around the circle 10 times? is …
Question #0993b - Socratic
Explanation: Given: #y^2=2x+3# and #y = x# Here is a graph of the two equations: graph { (2x+3-y^2) (y-x)=0 [-10, 10, -5, 5]} Solving these equations: #y^2=2x+3" [1 ...
What is the solution set for abs (2x – 4) = 10? | Socratic
Aug 29, 2015 · What is the solution set for |2x– 4| = 10? Algebra Linear Inequalities and Absolute Value Absolute Value Equations
Question #0be35 - Socratic
May 4, 2017 · We have the vertex (5,2), and the parabola has a negative a value because the graph is convex. Looking at the other point (4,1), we can tell that the a value is equal to -1 …
Choose the graph of this quadratic inequality? | Socratic
Apr 24, 2018 · The answer is the first graph: Given y^2-x^2/9 >= 1 We know that the equation: y^2-x^2/9 = 1 Is a hyperbola with a vertical transverse axis; this eliminates graphs 3 and 4 …
How do you solve #|x|=-5x+24# and find any extraneous …
The piecewise definition of |x| = { (x;x>=0), (-x;x<0):} allows one to separate the equation into two equations, one with x and the other with -x and then solve both equations. Check. Separate …